Paste: Advent of code 2016 day 2
Author: | razetime |
Mode: | prolog |
Date: | Sat, 15 Oct 2022 08:58:55 |
Plain Text |
:- module a02.
:- interface.
:- import_module io.
:- pred main(io::di,io::uo) is det.
:- type dir ---> u;d;l;r.
:- implementation.
:- import_module int,string,list,require.
:- pred p1(list(dir)::in,int::in,int::out) is det.
p1(D,S,F):-foldl(turn,D,S,F).
:- pred turn(int::in,dir::in,int::out) is det.
turn(S,l,E):-if S rem 3=0 then E=S else E=S-1.
turn(S,r,E):-if S rem 3=2 then E=S else E=S+1.
turn(S,u,E):-if S//3=0 then E=S else E=S-3.
turn(S,d,E):-if S//3=2 then E=S else E=S+3.
:- pred char_dir(character::in,dir::out) is det.
char_dir('U',u).
char_dir('D',d).
char_dir('L',l).
char_dir('R',r).
char_dir(_,_):-unexpected($pred,"'dir").
main(!IO):-
read_named_file_as_lines("inp/02",I,!IO),
(I=ok(L);
I=error(E),print(E,!IO),L=[]),
map((pred(X::in,Y::out) is det:-
string.to_char_list(X,Y0),
map(char_dir,Y0,Y)),L,Lc),
print(Lc,!IO),
nl(!IO).
Error:
a02.m:012: In clause for predicate `p1'/3:
a02.m:012: in argument 1 of call to predicate `foldl'/4:
a02.m:012: type error: type of argument does not match its expected type;
a02.m:012: argument has overloaded actual/expected types {
a02.m:012: (expected) `pred(
a02.m:012: L,
a02.m:012: A,
a02.m:012: A
a02.m:012: )',
a02.m:012: (expected) `pred(
a02.m:012: character,
a02.m:012: A,
a02.m:012: A
a02.m:012: )',
a02.m:012: (inferred) `pred(
a02.m:012: int,
a02.m:012: a02.dir,
a02.m:012: int
a02.m:012: )',
a02.m:012: (inferred) `pred(
a02.m:012: int,
a02.m:012: a02.dir,
a02.m:012: int
a02.m:012: )'
a02.m:012: }.
For more information, recompile with `-E'.
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